Question

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Answer 1

Answer:

$\huge{\underline{Question}}$

If sin B = cos(2B-30) Where 2B is an acute angle , then B =_____?

$\huge{\underline{Explanation:-}}$

Sin B = cos(2B- 30)...........(1) [given]

We know that,

Sin b = cos(90-B).........(2)

Now, from equation (1) & (2) we get:-

=> cos(2B-30) = cos(90-B)

Therefore,

=> 2B-30=90-B

=> 2B+B=90+30

=> 3B = 120

=> B = 120/3

=> B = 40

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Answer 2

hope it helps you dear

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