Question

question is..... particles moves through a distance of 15 m due south and then 8m due West...a) how much is the net displacement traversed.....b) what is the magnitude of the net displacement​

Answer 1

Answer:

write the given data

first a particle moves 3m north

which means in paper 3m right wards and a particle moves 4m north

and which means 4m upwards from the respective position

join the starting point of particle and ending point of particle by diagonal

now it is triangle

find hypopotenuse which is net displacement

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