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Given:
1.
2.
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What To Find:
We have to solve and check the equations.
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Solution 1:
Use cross multiplication,
⇒ 5x + 1 = 7 × 3
Multiply 7 and 3,
⇒ 5x + 1 = 21
Take 1 to RHS,
⇒ 5x = 21 - 1
Subtract 1 from 21,
⇒ 5x = 20
Take 5 to RHS,
⇒
Divide 20 by 5,
⇒ x = 4
Checking 1:
Subtitute the values,
⇒
Multiply and add the numerator,
⇒
Divide 21 by 3,
⇒ 7 = 7
∴ LHS = RHS
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Solution 2:
Take 3 as 3/1,
⇒
LCM of 3 and 1 is 3,
⇒
Take 3 to to LHS,
⇒ 5x + 9 = 3 (x + 7)
Multiply the brackets,
⇒ 5x + 9 = 3x + 21
Take 9 to RHS and 3x to LHS,
⇒ 5x - 3x = 21 - 9
Solve the bothe sides,
⇒ 2x = 12
Take 2 to RHS,
⇒
Divide 12 by 2,
⇒ x = 6
Checking 2:
Substitute the values,
⇒
Multiply the numerator,
⇒
Cancel 30 by 3,
⇒ 10 + 3 = 6 + 7
Solve both sides,
⇒ 13 = 13
∴ LHS = RHS
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