Question

Question is provided in the attachment above. Need a detailed answer, pls be kind enough to show your workings. If u don't know the answer feel free to skip!
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Answer 1

Explanation:

So an SHM equation is of the form

x(t)=A*sin(wt) where w=2π/T

So let's assume that at a time t¹, rhe displacement is A/1.41=A/√2

Putting t=t¹ and x=A/√2 in the equation for SHM, we get

A/√2=A*sin(wt¹)

-> 1/√2=sin(wt¹)

-> wt¹=π/4 or wt¹=3π/4

-> 2πt¹/T = π/4 or 2πt¹/T = 3π/4

-> t¹ = T/8 or T = 3T/8

Hence at times T/4 and 3T/4, the displacement is equal to A/1.41.

Answer 2

Answer:

IMAGINE

Explanation:

A/√2=A*sin(wt¹)

-> 1/√2=sin(wt¹)

-> wt¹=π/4 or wt¹=3π/4

-> 2πt¹/T = π/4 or 2πt¹/T = 3π/4

-> t¹ = T/8 or T = 3T/8