Question

❥︎Question༄
​ It is desried to prepare 500 g of solution. with 10% urea in water. How much urea should we dissolve in how much volume of water?
(density of water is 1 ml)​

Answer 1

Answer:

Mass by mass percentage of urea in water = 10%

Volume of solution = 500g

Mass by mass percent =

$\sf \: mass \: of \: solution \: \div \: mass \: of \: solute \: \times 100$

$\sf \: 10=mass \: of \: solute 500×100$

$\sf \: Mass \: of \: solute = \frac{10×500}{100 \times 50g}$

Mass of solvent (water) = mass of solution - mass of solute

Mass of solvent = (500−50)g=450g

Volume of solvent (water) =mass/ density

Volume of solvent (water) =450/ 1g/mL

Hence Answer is 450 ml

Answer 2

Explanation:

Mass by mass percentage of urea in water = 10%

Volume of solution = 500g

Mass by mass percent =

\sf \: mass \: of \: solution \: \div \: mass \: of \: solute \: \times 100massofsolution÷massofsolute×100

\sf \: 10=mass \: of \: solute 500×10010=massofsolute500×100

\sf \: Mass \: of \: solute = \frac{10×500}{100 \times 50g}Massofsolute=

100×50g

10×500

Mass of solvent (water) = mass of solution - mass of solute

Mass of solvent = (500−50)g=450g

Volume of solvent (water) =mass/ density

Volume of solvent (water) =450/ 1g/mL

Hence Answer is 450 ml