Question

* ⁺◦﹆◞˚ ꒰ Question ꒱
Mαss of α block metαl is 10 kg & its dimensions αre length 50 cm, breαdth 10 cm, height 20 cm. If the metαl block is plαced on the following surfαce on the tαble, find out on which of the surfαce ABCD, CDEF, & BCFG will the pressure exerted in the tαble be mαximum. (Refer the picture αttαched)

Answer 1

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Answer 2

First calculate Force applied on block .

• Mass of the block=10kg=m
• Acceleration due to gravity=g=10m/s^2

According to Newtons second law

$\boxed{\sf F=ma}$

$\\ \sf\longmapsto F=mg$

$\\ \sf\longmapsto F=10(10)$

$\\ \sf\longmapsto F=100N$

Formula of Pressure:-

$\boxed{\sf P=\dfrac{F}{A}}$

• P denotes to pressure
• F denotes to Force
• A denotes to Area

Calculate areas of each surfaces;-

ABCD:-

• Length=50cm
• Breadth=20cm

$\\ \sf\longmapsto Area=Length\times Breadth$

$\\ \sf\longmapsto Area=50\times 20$

$\\ \sf\longmapsto Area=1000cm^2=0.1m^2$

CDEF:-

• Length=50cm
• Breadth=10cm

$\\ \sf\longmapsto Area=50\times 10$

$\\ \sf\longmapsto Area=500cm^2=0.05m^2$

BCFG:-

• Length=20cm
• Breadth=10cm

$\\ \sf\longmapsto Area=20\times 10$

$\\ \sf\longmapsto Area=200cm^2=0.02m^2$

Calculate Pressures:-

ABCD

$\\ \sf\longmapsto P_{ABCD}=\dfrac{100}{0.1}$

$\\ \sf\longmapsto P_{ABCD}=1000Pa$

CDEF:-

$\\ \sf\longmapsto P_{CDEF}=\dfrac{100}{0.05}$

$\\ \sf\longmapsto P_{CDEF}=2000Pa$

BCFG:-

$\\ \sf\longmapsto P_{BCFG}=\dfrac{100}{0.02}$

$\\ \sf\longmapsto P_{BCFG}=5000Pa$

Observation:-

$\\ \sf\longmapsto 1000Pa\lt 2000Pa\lt 5000Pa$

$\\ \sf\longmapsto P_{ABCD}\lt P_{CDEF}\lt P_{BCFG}$

Conclusion:-

On BCFG surface the pressure is maximum