Question

Question ⤵

Mahesh's income is 20% more than Mohan's income but 20% less than Rahim's income. Tell Mohan's income is less than what percentage of Rahim's income?

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Answer 1

Question :-

Mahesh's income is 20% more than Mohan's income but 20% less than Rahim's income. Tell Mohan's income is less than what percentage of Rahim's income?

Solution :-

Suppose that Mohan's income = Rs.100

Mahesh's income = 100 + 20 ℅ = Rs.120

Now, let the income of rahim's = Rs.z

So Mahesh's income = z - z of 20℅

By question ,

z - z of 20 % = Mahesh's income = 80z/100 = 120

∴ z = ( 120 × 100 )/80 = Rs.150

Rahim's income = Rs.150

Mohan's income = Rs.100

Lack of = 50/150 × 100 = 100/3℅

Answer 2

Step-by-step explanation:

Given:-

Mahesh's income is 20% more than Mohan's income but 20% less than Rahim's income.

To find:-

Mohan's income is less than what percentage of Rahim's income?

Solution:-

Let the income of Mohan be Rs. X

Then Income of Mahesh = 20% more than Mohan's income

=> X + (20% of X)

=> X +( 20% × X)

=> X + (20/100)×X

=> X + (1/5)×X

=> X + (X/5)

=> (5X +X)/5

=> 6X/5

Mahesh's income = Rs. 6X/5----------(1)

Let the Rahim' s income be Rs. Y

The income of Mahesh = 20% less than Rahim's income

=> Y-(20% of Y)

=> Y - (20/100)×Y

=> Y - (1/5)×Y

=> Y - (Y/5)

=> (5Y-Y)/5

=> 4Y/5

Income of Mahesh = Rs. 4Y/5 ------------(2)

From (1)&(2)

=> (1)=(2)

=> 6X/5 = 4Y/5

=> 6X = 4Y

=>2×3×X = 2×2×Y

=> 3X = 2Y

=> X /Y = 2/3

=>X:Y = 2:3-----------(3)

Let Mohan's income is less than Z% percentage of Rahim's income

=>Z= (6X/5 - X)/(6X/5) × 100

=> Z = (6X-5X)/5/(6X/5) × 100

=> Z = (X/5)/(6X/5) × 100

=> Z = (1/6)×100

=> Z = 100/6

=>Z = 16.666...

=> Z = 16.67%

Answer:-

The required percentage for the given problem is 16.67%