Math, asked by mayureshkarande19, 2 months ago

Question Maths: 1) the length of a rectangle is 17cm and breadth is 15 cm . find the perimeter of the rectangle . 2) find the area of a square having side 12cm. 3) the length and Breadth of the page of a calendar is 45 cm and 26cm respectively . what is its area . please answer ​

Answers

Answered by shreyas34475
0

Answer:

the perimeter of rectangle=255

Answered by jackzzjck
9

SOLUTION - Q.1

Length of the rectangle = 17cm.

Breadth of the rectangle = 15cm.

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 17 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 15 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

Perimeter of a rectangle = 2(l+b) , Where l is the length and b is the breadth of the rectangle.

Here,

l = 17cm.

b = 15cm.

⇒ Perimeter of the rectangle = 2(17+15)

⇒ Perimeter of the rectangle = 2 × 32

⇒ Perimeter of the rectangle = 64cm.

SOLUTION - Q2

Sides of the Square = 12cm.

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(-0.5,-0.5){\bf D}\put(-0.5,4.2){\bf A}\put(4.2,-0.5){\bf C}\put(4.2,4.2){\bf B}\put(1.5,-0.6){\bf\large 12\ cm}\put(4.4,2){\bf\large 12\ cm}\end{picture}

Area of a square = a² , Where a is the side of the square.

Here,

a = 12cm.

⇒ Area of the square = (12)²

⇒ Area of the square = 144 cm².

SOLUTION - Q3

Length of the calendar = 45cm.

Breadth of the calendar = 26cm.

The calendar is in the shape of a rectangle .

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 45cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 26cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

Area of a rectangle = l × b , Where l is the length and b is the breadth of the rectangle.

⇒ Area of the calendar = 45 × 26

⇒ Area of the calendar = 1170 cm².

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