Question

Question :- Multiply (3x⁴-x²+6x-7) by (x²-3x +4).
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Answer 1

Answer:

see this

hopefully it helps you

Answer 2

• ${\large{\underbrace{\textsf{\textbf{\color{red}{➵}{\color{green}{\:\:αηѕωєʀ\: :-}}}}}}}$

$\tt ➪(3x^4−x^2+6x−7)(x^2−3x+4)$

$\tt ➪=(3x^4+−x^2+6x+−7)(x^2+−3x+4)$

$\tt ➪=(3x^4)(x^2)+(3x^4)(−3x)+(3x^4)(4)$

$\tt➪=3x^6−9x^5+12x^4−^x4+3x^3−4x2+6x^3$

$\tt ➪=3x^6−9x^5+11x^4+9x^3−29x^2+45x−28$