CBSE BOARD X, asked by ricky2642, 1 year ago

question nnnnnnnnnnnnnn

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ricky2642: pls answer this fast

Answers

Answered by joshuatauro45
1

In PQB

PQ^2=PO^2+OB^2

26^2=24^2 + OB^2

Therefore

OB^2=676-576

OB^2=100

OB=10

Const ON perpendicular to AB

OB^2=0N^2+NB^2

100=ON^+64(NB=8cm)

ON^2=36

ON=6cm

Therefore AB is 6cm from the centre

Answered by bhoomisurpaithankar1
0

Answer:

AB is 6cm from the centre

Explanation:

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