question nnnnnnnnnnnnnn
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ricky2642:
pls answer this fast
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In PQB
PQ^2=PO^2+OB^2
26^2=24^2 + OB^2
Therefore
OB^2=676-576
OB^2=100
OB=10
Const ON perpendicular to AB
OB^2=0N^2+NB^2
100=ON^+64(NB=8cm)
ON^2=36
ON=6cm
Therefore AB is 6cm from the centre
Answered by
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Answer:
AB is 6cm from the centre
Explanation:
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