Math, asked by deepak0916, 11 months ago

question no. 1 ................

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Answered by nikita8193
4
let the present age of Ani = x years
and peresent age of biju = y years

given that the ages of Ani and Biju differ by 3
= x- y = 3 ....(1)
given that
Ani's father dharam is twice as old as Ani
present age of dharam= 2x
And
Biju is twice as old as cathy
persent age of biju = 2× present age of cathy
present age of cathy = present age of biju/ 2
present age of Cathy = y/2 years

Also
the age of Dharam and Cathy differ by 30 years
2x - y/2 = 30
4x-y/2 = 30
4x-y = 60 .....(2)

hence the equations are
x-y =3 ......(1)
4x-y = 60......(2)

From equation 1
x-y = 3
x=3+y
putting x = 3+y in equation (2)
4x-y = 60
4(3+y) - y = 60
12 + 4y-y = 60
12 + 3y = 60
3y = 60 - 12
3y = 48
y = 48/ 3
y = 16

putting y = 16 in equation (1)
x - y =3
x = 3 + y
x = 3 + 16
x = 19

Therefore
Present age of Ani = 19 years
Present age of Biju = 16 years


rajmanish2: nice answer
Gurveer08: nice answer
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