question no 1 and 4.........
fast.
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So let's start with q no.1
1.6×10^-19 c constitute of 1 e-
so 1c " " " " " " " " " " " " " " "=1÷1.6×10^-19
=6.25×10-18 electrons
q no. 2
I'm assuming"p" as resistivity
p=R×a/l
p=2×10^-2×2÷1.7×10^-6
p=2.34×10^4
hope it helps
1.6×10^-19 c constitute of 1 e-
so 1c " " " " " " " " " " " " " " "=1÷1.6×10^-19
=6.25×10-18 electrons
q no. 2
I'm assuming"p" as resistivity
p=R×a/l
p=2×10^-2×2÷1.7×10^-6
p=2.34×10^4
hope it helps
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