Question no. 1 iii
How to do this.
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r th term of an ap= Tr
m th term of an ap= Tm
n th term of an ap= Tn
As indicated by question m.Tm=n.Tn
m(a + (m-1)d = n(a + (n-1)d)
Where an is the principal term and d is the normal distinction
mama – na + (m^2 – m)d - (n^2 –n)d
a(m-n) + d(m-n){m+n-1} = 0
a + (m+n-1)d = 0
Tm+n=0
Thus Proved
m th term of an ap= Tm
n th term of an ap= Tn
As indicated by question m.Tm=n.Tn
m(a + (m-1)d = n(a + (n-1)d)
Where an is the principal term and d is the normal distinction
mama – na + (m^2 – m)d - (n^2 –n)d
a(m-n) + d(m-n){m+n-1} = 0
a + (m+n-1)d = 0
Tm+n=0
Thus Proved
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