question no.10 and 12
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10) Principle=640
Amount=774.40
Time=2yrs
Rate=?
Amount=p(1+r/100)^n
=774.40=640(1+r/100)^2
774.40÷640=(1+r/100)^2
(11/10)^2=(1+r/100)^2
(Both powers are cut)
11/10=1+r/100
11/10-1/1=r/100
1/10=r/100
R=100/10
R=10%. Answer
Therefore rate %=10%.
12) Here is your answer......
Given :-
Principal = Rs.8000
Rate of interest = 5% per annum
Amount = Rs. 9261
Let Time (n) = 'n'
amount = p( 1+ r/100)^n
9261 = 8000(1+5/100)^n
9261/8000= (1+1/20)^n
(21/20)^3= (21/20)^n
then n = 3 years
I hope it is helped you
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Amount=774.40
Time=2yrs
Rate=?
Amount=p(1+r/100)^n
=774.40=640(1+r/100)^2
774.40÷640=(1+r/100)^2
(11/10)^2=(1+r/100)^2
(Both powers are cut)
11/10=1+r/100
11/10-1/1=r/100
1/10=r/100
R=100/10
R=10%. Answer
Therefore rate %=10%.
12) Here is your answer......
Given :-
Principal = Rs.8000
Rate of interest = 5% per annum
Amount = Rs. 9261
Let Time (n) = 'n'
amount = p( 1+ r/100)^n
9261 = 8000(1+5/100)^n
9261/8000= (1+1/20)^n
(21/20)^3= (21/20)^n
then n = 3 years
I hope it is helped you
follow me
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