Question no. 10
ASAP
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ajoychetry44167:
hey bro what is the name of this sample paper
don't know bro
do you think it's the latest paper
haha no
and by the way do you know about the changes made in cbse class x
i can see August 2018 mathematics in corner of page
no i don't know about changes in CBSE
thanks and bye bro
This is my school’s worksheet
ohh okay
Answers
Answered by
1
hey buddy here is your answer
for making a divisible take LCM of both number
520 and 468
we will get 2*2*2*3*3*5*13= 4680
for applying our condition in which we have to add 17 to make it divisible ...
Subtract 17 from LCM = 4680 - 17 = 4663 ( Answer )
this is the smallest number in which you can add 17 and it will b divisible with both of your eq .
hope it helps
for making a divisible take LCM of both number
520 and 468
we will get 2*2*2*3*3*5*13= 4680
for applying our condition in which we have to add 17 to make it divisible ...
Subtract 17 from LCM = 4680 - 17 = 4663 ( Answer )
this is the smallest number in which you can add 17 and it will b divisible with both of your eq .
hope it helps
Thanks
your welcome
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