Question

question no.10 plzz solve ​

Answer 1

according to question

radius of incircle in right angle triangle

r = ( a+b–c) / 2

so r = ( 14 + 48 – 50 ) / 2

r = 12/2 = 6 CM ans

here a = base b = perpendicular and c = hypotenuse.

hope it will be helpful.

Answer 2

Answer:

Step-by-step explanation:

First Pythagoras thm.

In ABC

Then you will get AC=50

Then with help of some const.

Join OC,OA,OB

NOW IN TRIANGLE ABC

AREA ABC= area of AOB+area of BOC +area of AOC

1/2*base*height = apply this formula

You will get area of triangle abc by ht. 14 and base 48

Area will be 336 something...

Now , leave radius as r only

And apply this formula on 3 short triangles

You will get 56r ( don’t try to fill the value of r

As radius will be Same from all sides)

Now divide 336 and 56 you will get

R=6