question no 12,13 please factorise this answer
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hayy mate here your answer ✔️ ✔️
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1) =((10•(a2))-(20a•(b2)))+(2•5b4)
= ((10 • (a2)) - (22•5ab2)) + (2•5b4)
=((2•5a2) - (22•5ab2)) + (2•5b4)
= 10 • (a2 - 2ab2 + b4) .
=a2 - 2ab2 + b4
=(a - b2)•(a - b2)
Detecting a perfect square :
a2 -2ab2 +b4 is a perfect square
It factors into (a-b2)•(a-b2)
which is another way of writing (a-b2)2
How to recognize a perfect square trinomial:
• It has three terms
• Two of its terms are perfect squares themselves
• The remaining term is twice the product of the square roots of the other two terms
=10 • (a - b2)2
2) 1 - 2ab - (a² + b²)
= 1 - 2ab - a² - b²
= 1 - (2ab + a² + b²)
= 1 - (a² + 2ab + b²)
= 1 - (a + b)(a + b)
= 1 - (a + b)²
= 1² - (a + b)² [1 - (a + b)][1 + (a + b)]
= [1 - a - b][1 + a + b]
= (1 - a - b)(1 + a + b)
______________________________
❣️⭐I hope you mark as brainlist answer⭐❣️✨✨
_____________________________
1) =((10•(a2))-(20a•(b2)))+(2•5b4)
= ((10 • (a2)) - (22•5ab2)) + (2•5b4)
=((2•5a2) - (22•5ab2)) + (2•5b4)
= 10 • (a2 - 2ab2 + b4) .
=a2 - 2ab2 + b4
=(a - b2)•(a - b2)
Detecting a perfect square :
a2 -2ab2 +b4 is a perfect square
It factors into (a-b2)•(a-b2)
which is another way of writing (a-b2)2
How to recognize a perfect square trinomial:
• It has three terms
• Two of its terms are perfect squares themselves
• The remaining term is twice the product of the square roots of the other two terms
=10 • (a - b2)2
2) 1 - 2ab - (a² + b²)
= 1 - 2ab - a² - b²
= 1 - (2ab + a² + b²)
= 1 - (a² + 2ab + b²)
= 1 - (a + b)(a + b)
= 1 - (a + b)²
= 1² - (a + b)² [1 - (a + b)][1 + (a + b)]
= [1 - a - b][1 + a + b]
= (1 - a - b)(1 + a + b)
______________________________
❣️⭐I hope you mark as brainlist answer⭐❣️✨✨
tina1772:
answer 2 is wrong
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