question no.12 of given image
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1
let 2 rupee coin be x, 5 rupee coin be y
therefore, x+y=36
=> x=36-y
therefore, 2x+5y=84
=> 2(36-y)+5y=84
=> 3y=12
=> y=4
therefore, there are 4 five rupee coins.
therefore, x+y=36
=> x=36-y
therefore, 2x+5y=84
=> 2(36-y)+5y=84
=> 3y=12
=> y=4
therefore, there are 4 five rupee coins.
Answered by
0
let the coins be x
₹2 coins = x
₹5 coins =36-x
A.T.Q.
2(x)+5(36-x)=84
2x+180-5x=84
180-84=5x-2x
96=3x
96÷3=x
32=x
so,
₹2 coins = x= 32 coins
₹5 coins =36-x= 4 coins
₹2 coins = x
₹5 coins =36-x
A.T.Q.
2(x)+5(36-x)=84
2x+180-5x=84
180-84=5x-2x
96=3x
96÷3=x
32=x
so,
₹2 coins = x= 32 coins
₹5 coins =36-x= 4 coins
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