Question

Question no. 12
Please solve this question

Answer 1

Question:

A number has two digits. The digit at tens place is four times the digit at units place. If 54 is subtracted from the number, The digits are reversed. Find the number.

Solution:

Let the digit at tens place = x

Let the digit at units place = y

So, the number is 10x + y

Given,

x = 4y (Equation 1)

Now,

The reversed number = 10y + x

According to question

10x + y - 54 = 10y + x (Equation 2)

Putting value of y in Equation 2 from Equation 1

10(4y) + y - 54 = 10y + 4y

40y + y - 54 = 14y

41y - 14y = 54

27y = 54

y = $\dfrac{54}{27}$

y = 2

Putting value in Equation 1

x = 4y

x = 4(2)

x = 8

Therefore, the required number 82.