Question No. 13 (2 The motion of a body is given by the equation du(t) 6.0 - 3v (t), wherev (t) is speed in m/s andt in sec. if body was at rest att 0 (A) The terminal speed is 2.0m/s (B) The speed varies with the time as v(t) = 2 (1 - e-31) m/s (C) The speed is 1.0m/s when the acceleration is half the initial value (D) The magnitude of the initial acceleration is 6.0m/s2
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The motion of a body is given by the equation dtdv=6−3v:where v is in m/s. If the body was at rest at t=0. (i) the terminal speed is 2 m/s. (ii) the magnitude of the initial acceleration is 6 m/s.
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