Math, asked by sahalmuhammed9, 1 day ago

Question No. 13 The surface area of the given cylinder is 440 cm2. If the cylinder is cut vertically across the centre, then what will be the total surface area (in cm2) of both parts? ​

Answers

Answered by blrkkc
0

Answer:

7 is the answer for your question

Answered by CuscoAnswers
0

Answer:

440

Step-by-step explanation:

You haven't given a radius but assuming your solving for the 13th question in BNAT Nov 2021 then the diameter given is 14. We are using a calculator here.

Cylinder formula: (2*pi*r)(r+h)

Now substitute r with 7

(2*pi*7)(7+h) = 440

now we need to get rid of (2*pi*7) so 440/(2*pi*7) = 440/43.9822972... which is roughly 440/44 which is 10

so now we have: 7+h = 10 so h = 10-7 = 3

h = 3

Now, the second part says that the cylinder is cut vertically so we assume this is in equal halves. so the equation is [(2*pi*r)(r+h)]/2 = (pi*r)(r+h)

Now let's plug our 2 numbers into this equation: (pi*7)(7+3) = 21.9911486*10 = 22*10 = 220.

Now we have the TSA of 1 of the parts so multiply our answer by 2 and we get 440.

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