Question

question no.14.....Equal masses of O2 , H2 and CH4 will have mole ratio of :- 1) 16:1:8. 2) 1:16:2. 3) 1:16:1 4) 16:1:16 ............ provide full process ​

Answer 1

Answer:

hey mate ✌✌

option 2 ✔✔

1:16:2

for full process, refer to the attachment.

Explanation:

hope it helps ✔✔

Answer 2

Answer:

AT STP one mole of gas =22.4 L

Therefore,

A) 32 g of O2 =22.4 L

1g of O2 =22.4/32 L

B) 2 g of H2 = 22.4 L

1g of H2= 22.4/2 L

C)16 g of methane= 22.4 L

1 g of methane = 22.4 /16 L

which means

(22.4/32): (22.4/2):(22.4/16)

simplifying we get ratio

1:16:2