Question

Question no.14
Write G between A and C
Question no.15
Write D on center point......plz help me to find the ans of both the qns​

Answer 1

$to \: prove$

A) TRAINGLE ABC is congruent to AFE

B) TRAINGLE AEG is congruent to ACG

$given$

ABDF is a square.

BC = FE

*(since, ABDF is a square all side will equal and measure of each angles will be 90°)

A) FOR TRAINGLE ABC AND AFE

BC = FE

therefore,

AFE = ABC = 90°

AF = AB ( shown above )

so TRAINGLE ABC is congruent to AFE

(SAS congruence criteria)

B ) FOR TRAINGLE AEG AND ACG

AG = AG ( common)

AGE = ACG ( since AG perpendicularly lies on EC mesure of AGE will be equal to ACG)

EAG = CAG ( since G bisect the angle A so mesure of each angles will be equal)

so TRAINGLE AEG is congruent to ACG ( ASA congruence criteria)

Mark as brainlist❤️

Answer 2

Step-by-step explanation:

Now, in question 14.

Given:- ABCD is a square of all sides are equal.

and BC=EF

To prove:- 1. ∆ABC cog. ∆AFE.

proof:- Now,in a ∆abc and ∆afe we have:-

BC=EF (given)

ang. AFE=ang.ABC (each =90deg.)

AB=AF (sides of square)

thus, ∆ABC cog. ∆AEF ( by SAS criteria).

By cpct AE=AC .

2. Now, in a ∆ACG and ∆AEG we have:-

AE =AC ( proved above)

AG=AG ( common).

EG=CG ( G is the midpoint of side CE)

thus, ∆ACG cog. ∆AEG ( by SSS criteria) .

Now, In question 15.

Given:- AB=AC and ang. DBC=ang.DCB.

To prove:-AD bisets ang. BAC.

proof:- we know that

AB = AC ang B =ang C ( side opp. to = angles are equal).

1/2ang B =1/2 ang C.

==ang DBC=ang DAC.

=== BD= CD.

So, Now, in a ∆ABD and ∆ACD we have:-

AB=AC ( given)

BD=CD ( proved above).

OA =OA ( common).

hence, ∆ABD cog. ∆ACD.( by SSS criteria) .

BY CPCT AD bisects ang. BAC.

Proved.

please, follow me and Thanks❤❤❤.