Question

Question no. 15 please help me

Answer 1

Answer:

27750

Step-by-step explanation:

Since 50 is added each day:

• the penalty for day 1 is 200 = 200 + 0 × 50;
• the penalty for day 2 is 250 = 200 + 1 × 50;
• the penalty for day 3 is 300 = 200 + 2 × 50;
• and so on.

The total penalty after 30 days is then

( 200 + 0 × 50 ) + ( 200 + 1 × 50 ) + ..... + ( 200 + 29 × 50 )

= 30 × 200 + ( 0 + 1 + 2 + ... + 29 ) × 50

= 6000 + ( 1 + 2 + ... + 29 ) × 50

= 6000 + (1/2) ( 29 ) ( 30 ) × 50

= 6000 + ( 29 ) ( 15 ) ( 50 )

= 6000 + 21750

= 27750

Answer 2

Answer:

Rs 27750

Step-by-step explanation:

Penalty is forming an AP

200 , 250 , 300 , ------

a = 200  = First Term

d = 50

n = 30

Last term = 30th term = a + (30-1)d

Last term = a + 29d

Last term = 200 + 29×50

Last term = 200 + 1450

Last term = 1650

Sum of 30 terms = (30/2) ( first term + Last Term)

= 15 × (200 + 1650)

= 15 × 1850

= 27750

so penalty amount to be paid by contractor would Rs 27750