question no 19..maths
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Given:- ab||cd, cd||ef and X:y=3:2
to find:- z
solve:- let X = 3a and y=2a
X+y = 180 (co-interior angles)
3a+2a=180
5a=180
a=36
x=108° and y=72°
x=z( alternate interior angles)
so, z= 108°
to find:- z
solve:- let X = 3a and y=2a
X+y = 180 (co-interior angles)
3a+2a=180
5a=180
a=36
x=108° and y=72°
x=z( alternate interior angles)
so, z= 108°
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