Question

Question no 2 and 3 solution

Answer 1

Taking gravity as -10 m/s2,
t=2s
u=0
s=ut+1/2 at2
=0+1/2×(-10)×2×2
=(-5)×2×2
=-20 m
Therefore the stones are separated by dist of 20 m when second stone is released.
Also, first stone has already travelled 20 m
Taking first stone,
t=12 s
u=0
a=-10 m/s2
s=ut+1/2 at2
=0+1/2×(-10)×12×12
=(-5)×12×12
=-720 m
Taking second stone,
t=10s
u=0
a=-10 m/s2
s=ut+1/2at2
=0+1/2×(-10)×10×10=-500m
Therefore distance between stones after 10s=720-500=220m
Since I did not take G=-9.81, so your answer should be D)215.6 m
Plz mark as brainliest :D