Question no.2 fast; Question no.2 fast
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It is given in the question that:
∠PBC < ∠QCB
Now,
∠ABC + ∠PBC = 180o
∠ABC = 180o - ∠PBC
Also,
∠ACB + ∠QCB = 180o
∠ACB = 180o - ∠QCB
Since,
∠PBC < ∠QCB therefore,
∠ABC > ∠ACB
Thus,
AC > AB as sides opposite to the larger angle is larger
∠PBC < ∠QCB
Now,
∠ABC + ∠PBC = 180o
∠ABC = 180o - ∠PBC
Also,
∠ACB + ∠QCB = 180o
∠ACB = 180o - ∠QCB
Since,
∠PBC < ∠QCB therefore,
∠ABC > ∠ACB
Thus,
AC > AB as sides opposite to the larger angle is larger
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