Question no 2: Parse a even/odd
string in such a way that as to divide
it to two halves of arrays.Suppose
let's consider a string 'FUTURITE',
divide it as [FUTU],[RITE], now here's
the logic if in case you get a odd
number of occurrences, we need to
do something like the following:Input:
KOLKATA Output:. [KOL] [K] [ATA] *
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Answer:
Time complexity of this solution is O(n2). Below is ... Java program to find the element occurring ... number of times. static int getOddOccurrence( int arr[], int arr_size ...
Explanation:
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