Question

Question No. 2
The position x of an object as function of time tis, x = 2+31 (where x is in metre and tis in second). The acceleration of the object at t = 2 s will be
4 m/s2
1 m/s2
2 m/s2
Zero​

Answer 1

I think your equation is x=2+3t

according to this equation :

if differentiate this equation with respect to dt

dx/dt=d/dt(2+3t)

v=3m/s 1

distance travel is given by at t=2

x=(2+3t)

x=(2+3*2)

x=8m

we can find acceleration of body by two ways

first:

by using equation of motions

second :

by diffrantiation of equation 1

dv/dt=d/dt(3)

a=0

since acceleration of body is zero