Question no 2
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According to the question
AP=PB
AD=BC
And APB is an equilateral triangle
It is proved that APD is congruent to BPC
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Answer:
APB is an equilateral triangle (given)
it is proved by side angle side property
●side -AP ~ BP (equilateral triangle)
●side -AP ~ BP (equilateral triangle)●angle- angle DAP ~ CBP( equilateral triangle in a square)
●side -AP ~ BP (equilateral triangle)●angle- angle DAP ~ CBP( equilateral triangle in a square)●side- AD~ CB (side of square are equal )
hence proved
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