question no. 21 and 22
Attachments:
dhruvbadaya1:
If you post it for 15 points or more, people will answer it.
Answers
Answered by
2
A21==>
x=3√3
⇒x-3√3=0
and, x=-3√3
⇒x+3√3=0
g(x)=(x-3√3)(x+3√3)
=x²-27
Now,
x²-27 ÷ x4 -2x3-26x2+54x-27
=x²-2x+1
now solvingv(x²-2x+1)
q(x)=x²-x-x+1
=x(x-1)-1(x-1)
=(x-1)(x-1)
Hence, other roots of the given polynomial are -1 and -1.
Similar questions