Math, asked by priyankjain227, 9 months ago

Question No. 21
What is the ratio of the area of a regular 12 sided polygon to the area of a regular octagon, if both the polygons are inscribed in the same circle?​

Answers

Answered by nidaeamann
0

Answer:

Ratio = 3/2.82

Step-by-step explanation:

A general formula for the area of a polygon having n number of sides which is inscribed inside a circle of radius r is given as;

Area = ½  x n x r2 sin(2π/n)

The value of n is 12 for a 12 sided polygon, putting this value;

Area of polygon = ½  x 12 x r2 sin(2π/12)

Area of polygon = 6 x r2 sin(30)

Area of polygon = 6 x r2 x 0.5

Area of polygon = 3 r2

The value of n is 8 for octagon, putting this value;

Area of octagon = ½  x 8 x r2 sin(2π/8)

Area of octagon = 4 x r2 sin(45)

Area of octagon = 4 x r2 x 0.707

Area of octagon = 2.82 r2

Ratio of Area of polygon to octagon = 3 r2/2.82r2

Ratio = 3/2.82

Answered by bestwriters
0

The ratio of the area of a regular polygon to the area of a regular octagon is 1.5 : 1.4

Step-by-step explanation:

The area of the polygon inscribed within circle is given by the formula:

A₁ = 1/2 × n × r² × sin(2π/n)

Where,

n = Number of sides = 12

On substituting the values, we get,

∴ A₁ = 1/2 × 12 × r² × sin(2π/12) = 6 × r² × sin(π/6)

The area of the octagon inscribed within circle is given by the formula:

A₂ = 1/2 × n × r² × sin(2π/n)

Where,

n = Number of sides = 8

On substituting the values, we get,

∴ A₂ = 1/2 × 8 × r² × sin(2π/8) = 4 × r² × sin(π/4)

From question, the circle is same. Thus,

6 × r² × sin(π/6) : 4 × r² × sin(π/4)

3 × sin(π/6) : 2 × sin(π/4)

3 × 0.5 : 2 × 0.70

∴ 1.5 : 1.4

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