Question

question no. 24

its my previous question which was not clear to viewers
plz tell

Answer 1

x^(p^q) = ( x^p)^q

or, x^(p^q) = x^(pq)

So..

p^q = pq

Taking log on both sides..
---------------------------------------
Log( p^q) = log(pq)

or, q×log (p) = log (p) + log(q)

or, log (p) ×(q - 1) = log (q)

or, log p = (log (q)) /(q-1)

or, p = e^{(log(q)) /(q-1))

or, p = [ e^(log(q))] ^1/(q-1)

or p = q ^( 1/(q-1))

Hence the answer is d.
______________________
Hope this is ur required answer.

Proud to help you.