Question

question no 25 solve friends

Answer 1

Angle A +angle B +angle C+angle K=360°
Angle A+angle B+55°+105°=360°
Angle A+angle B=200°. (1)
Now AP and BP are bisectors so
Angle PAB=angle PAK=1/2 KAB
And angle PBA= angle PBC=1/2 ABC
So divide (1) by 2
So angle A/2+Angle B/2=200/2 (2)
ANGLE PAB +ANGLE PBA=100°
NOW IN TRIANGLE PAB
ANGLE PAB+ANGLE PBA+ANGLE
APB=180
Angle APB=180-100. From (2)

Angle APB =80°