Chemistry, asked by likhithachowdary11, 1 month ago

Question No. 25 When an electron is revolving in 3rd Bohr orbit of H-atom, then (A) The no. of revolutions in one second is 2.43 x 1014 -15 (B) Time taken for one revolution is second is 4.11 x 10 (C) Energy of electron is 34.84 Kj/mole 0 (D) The radius of the orbit is 4.77A A​

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Answered by 4197priya
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