Question no 26's first no please ans
Attachments:
Answers
Answered by
0
Answer:
Q) 4sinA sin2A+1- 2 sin 2A=2sinA
a) A =30 A =15
Step-by-step explanation:
4sinA sin2A+1- 2 sin 2A=2sinA
4sinA sin2A+1- 2 sin 2A- 2sinA =0
2sin 2A ( 2sinA-1) -1(2sinA-1) =0
(2sin 2A -1) (2sin A-1) =0
Now solving these equations:
(2sin A-1) =0
sinA = 1/2
Sin A= Sin 30 ( coz sin 30 =1/2)
A = 30
(2sin 2A -1) =0
2sin 2A =1
sin2A = 1/2
sin 2A= sin 30 ( coz sin 30 =1/2)
2A = 30
A = 30/2 =15
Similar questions