Question

question no.2nd
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Answer 1

Given:-

☆In triangle ABC,AD is the perpendicular bisector of BC

To prove:-

☆Triangle ABC is isosceles in which AB=AC

Solution:-

In triangle ABC,we have:-

•AD perpendicular to BC

•BD=DC

In triangle ADB and ADC,we have:-

=>BD=DC (given,as AD bisects BC)

=>AD=AD (common)

=><ADB=<ADC=90°

Thus, Tri.ADB(congruent to)Tri.ADC (SAS criteria)

Hence,AB=AC (By C.P.C.T)

________________________________

Answer 2

Answer:

Given:-

☆In triangle ABC,AD is the perpendicular bisector of BC

To prove:-

☆Triangle ABC is isosceles in which AB=AC

Solution:-

In triangle ABC,we have:-

•AD perpendicular to BC

•BD=DC

In triangle ADB and ADC,we have:-

=>BD=DC (given,as AD bisects BC)

=>AD=AD (common)

=><ADB=<ADC=90°

Thus, Tri.ADB(congruent to)Tri.ADC (SAS criteria)

Hence,AB=AC (By C.P.C.T)

________________________________

Step-by-step explanation:

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