Question

Question No. 3
A sphere of radius Ris uniformly charged over its volume with positive charge density P. The potential at a point on its surface is 7., and the potential a
point P, at a distance r from its centre, is 117. Which of these option(s) is/are correct?
S
R
2
38
P=
HR
The magnitude of electric field at Pis
2R
Potential at all points inside the sphere is greater than 7​

Answer 1

Potential at x = 117 and potential on the surface (at R) is 7.

Explanation:

Potential at the center of sphere = Vc  = 3kQ / 2R

Potential at a distance x from the center = Vx = kQ/x

 kQ/x = 1/2 (3kQ / 2R)  

 we get x = 4R/3

So distance from the surface will be x - R = 4R/3 - R = R/3

Given potential at x = 117 and potential on the surface (at R) is 7.