question no 3 and 4
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Q3 x+y=6
x=6-y
x-y = 2
(6-y)-y=2
6-2y=2
-2y =2-6
y= -4/-2
y=2
x+y=6
x+2=6
x=6-2=4
therefore, x=4 and y=2
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