Question

Question no 3 class 10 chapter 14 exercise 14.1

Answer 1

Now , we have to find the value of f .....

fi = 44 +f .

fidi = 2f - 40

x = a + $\dfrac{ fidi }{fi }$

18 = 18 + $\dfrac{ 2f - 40}{44+f}$

18 - 18 = $\dfrac{ 2f - 40 }{44+f}$

0 = $\dfrac{2f - 40 }{44 + f }$

2f - 40 = 0 .

2f = 40

f = $\dfrac{40}{2}$