Question No.3
In the given circuit, calculate the total current flowing though the circuit.
Answers
Answer:
2 A
Explanation:
Here,
Resistances of 5 ohm and 20 ohm are in series combination( for their own ) whereas they are in parallel combination for the effective resistance of series combination of 15 ohm and 10 ohm.
Effective resistance of 5 ohm and 20 ohm is ( 5 + 20 ) ohm or 25 ohm.
Effective resistance O 15 ohm and 10 ohm is ( 15 + 10 ) ohm or 25 ohm.
Total effective resistance is reciprocal of 1 / 25 + 1 / 25
= > Effective resistance is ( 25 x 25 ) / ( 25 + 25 ) => 25 / 2 => 12.5 ohm.
Therefore,
= > Current I = V / R
= > Current = 25 / 12.5 A
= > Current = 2 A
= > Current = 2 A
Answer: 2 A
Firstly see the figure u have four resistor
Upper are in series and lower one are in series and last these two are in parallel so net resistance = 12.5 ohm
At last to find I by ohms low
V=IR so I= v/r
I= 2 A answer
Explanation: