Math, asked by sana5423, 3 months ago

Question No. 3 of 15 Morka
Pipe A and B can fill a tank in 15 and 18 minutes but pipe C can empty it in 6 minutes. Pipe A
and B are kept open for 5 minutes in the beginning and then pipe is also opened, In what
time is the cisterns emptied)​

Answers

Answered by amitnrw
3

Given : Pipe A and B can fill a tank in 15 and 18 minutes

pipe C can empty it in 6 minutes

Pipe A and B are kept open for 5 minutes in the beginning

then pipe C is also opened

To Find : In  what time is the cisterns emptied

Solution:

Pipe A and B can fill a tank in 15 and 18 minutes

=> Pipe A and B together can fill in 1 min = 1/15 + 1/18

= ( 6 + 5)/90

= 11/90

Filled in 5 Minutes  =  5 * 11/90  =  55/90  

Pipe C can empty it in 6 minutes

Pipe C can empty in 1 minute = 1/6

Pipe A , B & C together in 1 Min  can empty  =  1/6  - 11/90

= ( 15 - 11)/90

= 4/90

4/90  Emptied   in   1 Min

55 90 emptied   in  =   55/4      min

= 13.75 Mins

= 13 mins 45 sec  after  Pipe C opened

Learn More:

A pipe can fill the tank in 20 min and another pipe can fill the tank

https://brainly.in/question/9388454

Two pipes a and b can fill a cistern in 12 min and 16 min ...

https://brainly.in/question/9219024

Answered by krishna210398
0

Given,

Pipe A and B can fill a tank in 15 and 18 minutes

Pipe C can empty it in 6 minutes

Pipe A and B are kept open for 5 minutes in the beginning

Pipe C is also opened

To find, In  what time is the cisterns emptied

Solution:

Pipe A and B can fill a tank in 15 and 18 minutes

=> Pipe A and B together can fill in 1 min = 1/15 + 1/18

= ( 6 + 5)/90

= 11/90

Filled in 5 Minutes  =  5 * 11/90  =  55/90  

Pipe C can empty it in 6 minutes

Pipe C can empty in 1 minute = 1/6

Pipe A , B & C together in 1 Min  can empty  =  1/6  - 11/90

= ( 15 - 11)/90

= 4/90

4/90  Emptied   in   1 Min

55 90 emptied   in  =   55/4      min

= 13.75 Mins

= 13 mins 45 sec  after  Pipe C opened

#SPJ2

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