Question no. 3 solve plz
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Answered by
1
-1 is your answer
mark me as brainleist
For both Left hand limit and right hand limit, the value will be the same. I will just show it for the left hand limit. You can work on similar lines to achieve RHL.
limx→1−(1−x+[x−1]+[1−x])limx→1−(1−x+[x−1]+[1−x])
For left hand limit x-1 will tend to 0
However for greatest integer function (second term) since x is slightly lesser than 1, x-1 tends to left side of zero and that under G.I.F. will be equal to -1.
For the third term since x is lesser than 1, 1-x will tend to right side of 0 and that under the G.I.F. will be equal to zero.
So the final limit will be equal to 0–1+0 = -1
Hope it helps
mark me as brainleist
For both Left hand limit and right hand limit, the value will be the same. I will just show it for the left hand limit. You can work on similar lines to achieve RHL.
limx→1−(1−x+[x−1]+[1−x])limx→1−(1−x+[x−1]+[1−x])
For left hand limit x-1 will tend to 0
However for greatest integer function (second term) since x is slightly lesser than 1, x-1 tends to left side of zero and that under G.I.F. will be equal to -1.
For the third term since x is lesser than 1, 1-x will tend to right side of 0 and that under the G.I.F. will be equal to zero.
So the final limit will be equal to 0–1+0 = -1
Hope it helps
Sriparno:
can you show me the method ?
Answered by
4
I think your answer is -1
Hope it helps
Hope it helps
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