Question

Question No.3
Trains A and B start moving at the same time from stations X and Y respectively towards each other on parallel tracks, Aftor passing each other, A and B take x hours and 8 hours to
roach Y and X, respectively. If the speed of B ls 25% more than that of A, then what is the value of ?
10​

Answer 1

Answer:

12 1/2 = 25/2 will be the Answer

Answer 2

question correct

Trains A &B start moving at the same time from stations X & Y respectively towards each other on parallel tracks. After passing each other, A & B take x hours and 8 hours to reach Y & X, respectively. If the speed of B ls %  more than that of A, then what is the value of x?

Answer:

The value of  x is 5.12 hrs.

Step-by-step explanation:

Given:

Trains A & B start moving at the same time from stations X & Y respectively towards each other on parallel tracks.

After passing each other, A and B take x hours and 8 hours to

roach Y & X, respectively.

The speed of B ls % 25 more than that of A.

To Find:

The value of  x.

Formula Used:

 $(\frac{Speed\ of\ A}{Speed\ of\ B} )^{2} =\frac{T1}{T2}$-------------- formula no.1.

Where

 T1 and T2 are respective time taken by train A &B after meeting each other.

Solution:

Let speed of train A is r km/hr.

Speed of train B $=r( 1+\frac{25}{100} )$

                   $=r(\frac{ 125}{100} ) =1.25r$ km/hr

Time taken by  train A after meeting = x hrs.

Time taken by train  B after meeting = 8 hrs.

Applying formula no.1.

$(\frac{Speed\ of\ A}{Speed\ of\ B} )^{2} =\frac{T1}{T2}$

$(\frac{r}{1.25\ r} )^{2} =\frac{x}{8}$

$(\frac{1}{1.25} )^{2} =\frac{x}{8}$

$x =\frac{8}{1.25^{2} }$

$x =\frac{8}{1.56 }$

$x=5.12\ hrs$

Thus,the value of x is 5.12 hr.

Project Code # SPJ3