question no.30....plzz ans....thnx
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Let, first digit = x
second digit = y
x+y=7 , y=7-x
No. Is 10x+y
When,
No. Becomes 10y+x
Then,
10y+x+3 = 40x+4y
10y-4y+x-40x=-3
6y-39x=-3
Now,
6(7-x)-39x=-3
42-6x-39x=-3
-45x=-3-42
x=45/45
x=1
Now, y=7-1 = 6
Therefore required no. Is 16
Hope it helps
second digit = y
x+y=7 , y=7-x
No. Is 10x+y
When,
No. Becomes 10y+x
Then,
10y+x+3 = 40x+4y
10y-4y+x-40x=-3
6y-39x=-3
Now,
6(7-x)-39x=-3
42-6x-39x=-3
-45x=-3-42
x=45/45
x=1
Now, y=7-1 = 6
Therefore required no. Is 16
Hope it helps
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