Question No. 34
plz solve this problem
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x=asin(theta)
or, x²= a²sin²(theta)
y=bcos(theta)
or, y²=b²cos²(theta)
(b²x²+a²y²)
=(b²a²sin²(theta) +a²b²cos²(theta))
=(a²+b²)(sin²(theta)+cos²(theta))
=(a²+b²). [because sin²x+cos²x=1]
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