Question no. ,35 please give me the answer of this question
Attachments:
Answers
Answered by
1
Sin 15 = sin ( 45 - 30)
= sin 45 cos 30 - cos45 sin30
=( 1/ root2) (root3 / 2) - ( 1/ root2) ( 1/2)
= root3 / 2 root2 - 1 / 2 root2
= root3 - 1 / 2 root2
COS 15 = cos ( 45 - 30)
= cos45 cos 30 + sin 45 sin 30
= ( 1/ root2) ( root3 /2) + (1/ root2) ( 1/2)
= root3 / 2 root2 + 1 / 2 root2
= root3 + 1 / 2 root2
Hope it helps you
= sin 45 cos 30 - cos45 sin30
=( 1/ root2) (root3 / 2) - ( 1/ root2) ( 1/2)
= root3 / 2 root2 - 1 / 2 root2
= root3 - 1 / 2 root2
COS 15 = cos ( 45 - 30)
= cos45 cos 30 + sin 45 sin 30
= ( 1/ root2) ( root3 /2) + (1/ root2) ( 1/2)
= root3 / 2 root2 + 1 / 2 root2
= root3 + 1 / 2 root2
Hope it helps you
gauravch047:
All right
Similar questions