Question

Question No. 39
• Carius method, 0.301 g of an
organic substance when heated with
excess of strong nitric acid and silver
nitrate gave 0.3066 g of silver
bromide. Find the % bromine in the
compounds.
Answer
A. 47.20%
B. 41.61 %
C. 26.20 %
D. 43.34%​

Answer 1

Answer:

sorry 8 am not getting the answer

Answer 2

Given :

Mass of the organic compound taken = 0.301 g

Mass of Silver bromide (AgBr) formed = 0.3066 g

To Find :

Percentage of bromine in the compound.

Solution :

We know, 1 mol of AgBr = 1 gram atom of Br

or,             188 g of AgBr = 80 g of Br

i.e., 188 g of AgBr contain = 80 g of Br

∴ 0.3066 g of AgBr contain = $\frac{80}{188}$ × 0.3066 g of Bromine

This amount of Bromine is present in 0.301 g of organic Compound.

∴ Percentage of Bromine = $\frac{80}{188}$ × $\frac{0.3066}{0.301}$ × 100

                                          = 43.34%

∴ The percentage of Bromine in the organic compound is 43.34%.

The correct option is (D) 43.34%