Question

Question No. 4
A volume of hall is 6900 cubic
metres and its total surface area of
absorption of sound is 300 sq. m.
Calculate the reverberation time of
the hall.​

Answer 1

Explanation:

given: 6900

total sarface area=6a^2

6900/6

1150sq.m.

Answer 2

Given: Volume of the hall = 6900 m³

The surface area of absorption = 300 m²

To Find: Reverberation time of the Hall

Solution:

Sabine's formula is given as

RT = 0.049 $\frac{V}{a}$, where RT is the reverberation time, V is the volume of the room and a is total surface area that absorbs the sound.

RT = $0.049\frac{6900}{300}$

    = 0.049 x 23

    = 1.127 seconds.

Therefore, the reverberation time is 1.127 seconds.

What is reverberation time?

When a sound is made is stays in the surrounding for a while and sometimes gets reflected to create an echo. Reverberation is the time after which the sound is no longer present in the room. It is absorbed by rough surfaces like curtains, carpets, etc. Reverberation time is the time for which the sound stays in the room before being absorbed.