Question

Question no 4 and 5 ​

Answer 1

Answer:

hope it helps you.

Explanation:

1.Consider a body of mass “m” having initial velocity “u”. Let after time “t” its final velocity becomes “v” due to uniform acceleration “a”. This is the first equation of motion. ... This is the third equation of motion.

2.

Answer:

Given parameters

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

u=18×100060×60s

u = 5 m/s

Final velocity (v) =36km/hour

v=36×100060×60s

v =10 m/s

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m